abigailgillman94 abigailgillman94

16-09-2020
Physics

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Gold has a specific heat of 129 J/kg K. How much heat would be given off when 50 kg of gold cools from 323 kg to 293 kg?

Respuesta :

kk5996282 kk5996282

28-09-2020

Answer:

Explanation:

Q=m*c*ΔT

m=50 kG

C=129 j.kg^-1.k^-1

ΔT=323-293=30

now

Q=50*129*30=193500

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