hebaqabdo910 hebaqabdo910

19-08-2020
Chemistry

contestada

Given 57 grams of NO2,

A. How many moles of NO2, are present?

B. How many atoms of oxygen are present?

Respuesta :

rakibul3 rakibul3

19-08-2020

Answer:

N=14 O=16

Explanation:

46 g = 1 mole of NO2

Now, 57g =(1/46) ×57 mole of NO2

= 1.24 mole of NO2

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