obekpe5
obekpe5 obekpe5
  • 19-08-2020
  • Mathematics
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Quadratic and Ratios...​

Quadratic and Ratios class=

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CSMedrano
CSMedrano CSMedrano
  • 19-08-2020

Answer:

x=0

Step-by-step explanation:

in the quadratic formula to only have one solution

[tex]b^{2} -4ac=0[/tex] for [tex]ax^2+bx+c=0[/tex]

so we have

[tex]ax^2+b=c[/tex]

[tex]ax^2+(b-c)=0[/tex]

if we insert in the formula we have

[tex]0^2-4(a)(b-c)=0\\\\-4ab+4ac=0\\\\4ac=4ab\\\\\frac{4ac}{4a} = \frac{4ab}{4a}\\\\c=b[/tex]

[tex]ax^2+b=c\\\\ax^2=b-b\\\\ax^2=0[/tex] since a≠0

[tex]\frac{ax^2}{a}=\frac{0}{a} \\\\x^2=0\\\\x=0[/tex]

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