What is the pressure in millimeters of mercury of 0.0150 mol of helium gas with a volume of 213 mL at 50. C? (Hint: You must convert each quantity into the correct units (L, atm, mol and K) before substituting into the ideal gas law.)

Respuesta :

Explanation:

0.08206 L atm mol-1K-1

pv=nRT

Px213 x10^-³ = 0.0150 x 0.08206 x 323

px213 x10^-³ = 0.398

p = 0.398/213 x10^-³

p = 1.87 x 10^-6atm

p = 0.0014mmHg

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