Answer:
2√x can be written as
[tex] {2x}^{ \frac{1}{2} } [/tex]
So we have
[tex] {2x}^{ \frac{1}{2} } \times {4x}^{ - \frac{5}{2} } \\ = {2x}^{ \frac{1}{2} } \times {2x}^{- \frac{5}{2} \times 2 } \\ \\ = {2x}^{ \frac{1}{2} } \times {2x}^- {5} \\ \\ = {2x}^{ \frac{1}{2} - 5 } \\ \\ = {2x}^{ -\frac{9}{2} } [/tex]
Comparing with k.x^n
k = 2 n = -9/2
Hope this helps you
