bholaramsewkumar806
bholaramsewkumar806 bholaramsewkumar806
  • 17-07-2020
  • Mathematics
contestada

Please help me I’m desperate

Please help me Im desperate class=

Respuesta :

unicorn3125
unicorn3125 unicorn3125
  • 17-07-2020

Answer:

           The first

Step-by-step explanation:

[tex]\frac29x+3>4\frac59\\{}\quad-3\quad-3\\\\\frac29x\ >\ 1\frac59\\\div\frac29\quad \, \div\frac29\\\\x>1\frac59\div\frac29\\\\x>\frac{14}9\times\frac92\\\\x>\frac{7}1\times\frac11\\\\x>7[/tex]

That means every x wich is greater than 7

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