omarrojas05 omarrojas05
  • 21-06-2020
  • Mathematics
contestada

Find the values of a , b , c in the equation
(X^5yz^4)^3\x^3yz=x^ay^bz^c

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 21-06-2020

Answer:

  (a, b, c) = (12, 2, 11)

Step-by-step explanation:

We assume you want to simplify ...

  [tex]\dfrac{(x^5yz^4)^3}{x^3yz}=x^{3\cdot 5-3}y^{3\cdot 1-1}z^{3\cdot 4-1}=x^{12}y^2z^{11}[/tex]

Compared to (x^a)(y^b)(z^c), we find that ...

  (a, b, c) = (12, 2, 11)

_____

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (ab)^c = (a^c)(b^c)

  (a^b)/(a^c) = a^(b-c)

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