jujuko12
jujuko12 jujuko12
  • 20-06-2020
  • Mathematics
contestada

f(x)=x^2-2x+3; f(x)=-2x+28

fxx22x3 fx2x28 class=

Respuesta :

Alfpfeu
Alfpfeu Alfpfeu
  • 20-06-2020

Answer:

(-5, 38) and

(5,18)

Step-by-step explanation:

[tex]x^2-2x+3=-2x+28\\<=> x^2-2x+3+2x=28\\<=> x^2 = 28-3=25\\<=> x^2-25=0\\<=> x^2-5^2 =0\\<=> (x-5)(x+5)=0\\<=> x = 5 \ or \ x=-5[/tex]

so the solutions are

(-5, 38) and

(5,18)

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