haifaasim haifaasim
  • 19-06-2020
  • Mathematics
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Prove that: (1+cot^2x)tan^2x = sec^2x

Respuesta :

Bebong Bebong
  • 19-06-2020

Answer:

Step-by-step explanation:

[tex]1+cot^2x = csc^2x= \frac{1}{sin^2x}[/tex]

it becomes

[tex]\frac{1}{sin^2x}*\frac{sin^2x}{cos^2x}=\frac{1}{cos^2x}=sec^2x[/tex]

Done

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