Answer:
Q = 114895 J
Explanation:
To find the thermal energy gained by the ice you use the following formula:
[tex]Q=mc(T_2-T_1)+H_f\ m[/tex]
m: mass of the ice = 0.250kg
T2: final temperature = 22°C
T1: initial temperature = -8.0°C
Hf: heat of fusion of water = 3.34*10^5 J/kg
c: specific heat of water = 4186 J/kg
By replacing the values of the parameters you have:
[tex]Q=(0.250kg)(4186J/kg\°C)(22+8)\°C+(3.34*10^5 J/kg)(0.250kg)\\\\Q=114895\ J[/tex]
where you have considered that ice melts completely
