Answer: P(A∪B)=0.72. The answer is provided below.
Step-by-step explanation:
Sue travels by bus or walks whenever she goes to the shops.
Probability of (catching the bus to shop ), P(A)= 0.4
Probability of (catching the bus from the shop ), P(B) = 0.7
Both of the events A and B are independent events.
Therefore, P(A∩B) = 0.4 × 0.7
= 0.28
Probability that Sue walks one way will be = 1 - P(A∩B)
= 1 - 0.28
= 0.72
Hence, the probability that Sue will walk at one way is 0.72
