marcellabella9 marcellabella9
  • 18-05-2020
  • Chemistry
contestada

How many moles of oxygen are required to react completely with 16.5 mol Al?

Respuesta :

SvetkaChem
SvetkaChem SvetkaChem
  • 18-05-2020

Answer:

12.4 mol O2

Explanation:

                                4Al +       3O2 -----> 2Al2O3

from reaction          4 mol        3 mol

given                    16.5 mol       x mol

x = 16.5*3/4 =12.4 mol    O2

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