Respuesta :

mathstudent55

Answer:

[tex] $\sum_{n=1}^{5} 6(2^{n-1}) $ [/tex]

Step-by-step explanation:

6 + 12 + 24 + 48 + 96 =

= 6 + 6 * 2 + 6 * 4 + 6 * 8 + 6 * 16

= 6 + 6 * 2^2 + 6 * 2^2 + 6 * 2^3 + 6 * 2 * 4

= 6 * 2^(n - 1)

[tex] $\sum_{n=1}^{5} 6(2^{n-1}) $ [/tex]