Respuesta :

haileymoe
f (x)=y
y=2x-9


X Y
-2 -15 y=2 (-2)-9
y=-4+-9
y=-15

-1 -11 y=2 (-1)-9
y=-2+-9
y=-11

0 -9 y=2 (0)-9
y=0+-9
y=-9

1 -7 y=2 (1)-9
y=2+-9
y=-1

2 -5 y=2 (2)-9
y=4+-9
y=-5

Here is all the work
Ckaranja
Let f(x)=y
y=[tex] x^{2} -9[/tex]
Make x the subject of the formula;
y+9=[tex] x^{2} [/tex]
x=[tex] \sqrt{y+9} [/tex]
So, the inverse of the function is thus;
[tex] f^{'} = \sqrt{x+9} [/tex]

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