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18-08-2016
Chemistry

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what is the ph of a solution with [oh-] = 2.6 × 10^-3 m?

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Willchemistry Willchemistry

19-08-2016

pOH = - log [ OH⁻]

pOH = - log [ 2.6x10⁻³]

pOH = 2.58

pH + pOH = 14

pH + 2.58 = 14

pH = 14 - 2.58

pH = 11.42

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