Answer:
A.) ∆KHM ≅ ∆KJM
Step-by-step explanation:
In triangle KHJ, KM is the bisector of base HJ..(given)
[tex] \therefore \: HM \cong \: JM...(1) \\ In\: \triangle KHM \:\& \: \triangle KJM\\
KH\cong KJ... (given) \\
KM \cong KM.. (common\: side) \\
HM \cong JM... [From\: equation \: (1)]\\
\therefore \triangle KHM \cong\triangle KJM\\.. (By\:SSS\: Postulate) \\ [/tex]
