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6. The temperature of an iron block decreases from 85°C to 25°C. If the mass for
the block is 1.2 kg, calculate the heat lost by the block. (Citon = 0.115 cal/g.°C)

Respuesta :

Answer:

8280 cal

Step-by-step explanation:

Q=mc(delta)T

Q=1200(0.115)(-60)

Q=8280 cal

I used 1200 g instead of 1.2 kg

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