Answer:
[tex] \frac{22\pi }{3} \: m[/tex]
Step-by-step explanation:
[tex]central \: \angle ( \theta)\: for \: major \: arc \\ = 360 \degree - 30 \degree = 330 \degree \\ radius \: (r) = 4 \: m \\ length \: of \: major \: \overset{\frown} {ACB} \: \\ = \frac{ \theta}{360 \degree}\times 2\pi \: r \\ \\ = \frac{ 330 \degree}{360 \degree}\times 2 \pi \times 4 \\ \\ = \frac{ 11 }{12}\times 2 \pi \times 4 \\ \\ = \frac{22\pi }{3} \: m[/tex]
