Respuesta :

dalendrk
[tex]\log_ab=c\iff a^c=b\\\\\log_816=x\iff8^x=16\\\\8=2^3;\ 16=2^4\\\\therefore\\\\8^x=16\to(2^3)^x=2^4\\\\2^{3x}=2^4\iff3x=4\ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=\dfrac{4}{3}}\to\fbox{C.} [/tex]