Respuesta :

dalendrk
[tex]\dfrac{2x\pm1}{5x^2-x}\\\\it's\ unde fined\ when\ 5x^2-x=0\\\\x(5x-1)0\iff x=0\ or\ 5x-1=0\\\\x=0\ or\ 5x=1\\\\\boxed{x=0\ or\ x=\frac{1}{5}}[/tex]