Answer:
The graph of the line is attached below.
Step-by-step explanation:
According to the slope-intercept form
[tex]y=mx+b[/tex]
As the line equation is given by
[tex]y=\:-3x\:-\:2\\[/tex]
[tex]\mathrm{Slope\:of\:}-3x-2:\quad m=-3[/tex]
y-intercept = b = -2
[tex]\mathrm{Axis\:interception\:points\:of}\:-3x-2:\quad \mathrm{X\:Intercepts}:\:\left(-\frac{2}{3},\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-2\right)[/tex]
- [tex]\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0[/tex]
[tex]-3x-2=0:\quad x=-\frac{2}{3}[/tex]
[tex]\mathrm{X\:Intercepts}:\:\left(-\frac{2}{3},\:0\right)[/tex]
- [tex]y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0[/tex]
[tex]y=-3\cdot \:0-2:\quad y=-2\\[/tex]
[tex]\mathrm{Y\:Intercepts}:\:\left(0,\:-2\right)[/tex]
The graph of the line is attached below.
