mindyaownb mindyaownb
  • 20-03-2020
  • Mathematics
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y=1/6x+3 and contains the point (-3,23) what is the equation of its perpendicular line

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szetosarahg
szetosarahg szetosarahg
  • 20-03-2020

Answer:

y = -6x + 5

Step-by-step explanation:

The first thing you should know about a perpendicular line is that the slope is the opposite reciprocal. So, this is your current equation: y= -6x + b. Plug in your coordinate to the equation to get this: 23 = -6(-3) + b. Multiply -6 by -3 to get 18. This is what is should look like: 23 = 18 + b. Subtract 18 from both sides to get your y-intercept of 5. Go back to your original equation and plug in 5 to b. This is your final equation: y = -6x + 5. Hope this helped!

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