Answer:
[tex]h^{-1}[/tex](x) = [tex]\frac{4x-48}{3}[/tex]
Step-by-step explanation:
let y = h(x) and rearrange making x the subject, that is
y = [tex]\frac{3}{4}[/tex] x + 12 ( multiply through by 4 to clear the fraction )
4y = 3x + 48 ( subtract 48 from both sides )
4y - 48 = 3x ( divide both sides by 3 )
[tex]\frac{4y-48}{3}[/tex] = x
Change y back into terms of x, thus
[tex]h^{-1}[/tex] (x) = [tex]\frac{4x-48}{3}[/tex]
