For this case we should find the solution of the following equation:
[tex]e^{ 0.5x} = 0.5[/tex]
For properties of Neperian and exponential logarithm we have to:
[tex]ln(e^{0.5x})=ln(0.5)[/tex]
So, applying Neperian logarithm to both sides of the equation we have:
[tex]0.5x = ln (0.5)\\0.5x = -0.69315\\x = \frac {-0.69315} {0.5}\\x = -1.39[/tex]
Answer:
[tex]x=-1.39[/tex]
