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large electroscope is made with "leaves" that are 78-cm-long wires with tiny 43 g spheres at the ends. When charged, nearly all the charge resides on the spheres. If the wires each make a 26∘ angle with the vertical , what total charge Q must have been applied to the electroscope?

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We have that the the total charge on electroscope applied i

  • q_e=6.52 *10^-6 C

From the question we are told

  • large electroscope is made with "leaves" that are 78-cm-long wires with tiny 43 g spheres at the ends.
  • When charged, nearly all the charge resides on the spheres. If the wires each make a 26∘ angle with the vertical
  • what total charge Q must have been applied to the electroscope?

total charge on electroscope

Generally the equation for the balancing the forces on a wire   is mathematically given as

[tex]T * cos(26) = m\\\\T * sin(26) = F\\\\Hence\\\\tan(26) =\frac{F}{(m * g)}\\\\\tan(26) = \frac{F}{(0.043 * 9.8)}\\\\\F = 0.206 N\\\\\Now to find charge\\\\\frac{k * q^2}{( 2 * 0.78 * sin(26))^2} = F\\\\\q = 3.26 *10^{-6} C[/tex]

Hence the total charge on electroscope applied i

  • q_e=6.52 *10^-6 C

For more information on electroscope visit

https://brainly.com/question/16517842

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