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When an aqueous solution of strontium chloride is added to an aqueous solution of potassium sulfate, a precipitation reaction occurs. Write the balanced net ionic equation of the reaction. Include charges on the ions, where applicable. Include coefficients only when they are different than ?

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Answer:

[tex]2Cl^{-}_{(aq)} + 2K^{-} _{(aq)} = 2KClx_{(aq)}[/tex]

Explanation:

The reaction is a precipitation reaction. In other words, the two aqueous solutions react to give the solid salt, potassium chloride (KCl) in this case.

[tex]SrCl_{2} _{(aq)} + K_{2}SO_{4} _{(s)} = SrSO_{4} _{(aq)} + 2KCl_{(s)}[/tex]

Because the reaction product is a solid, the net ionic equation can be written as:

[tex]2Cl^{-}_{(aq)} + 2K^{-} _{(aq)} = 2KClx_{(aq)}[/tex]

This is the resultant equation after removing spectator ions: sulfate and strontium.

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