The slope of the line that contains the point (13,-2) and (3,-2) is 0
Solution:
Given that we have to find the slope of the line
The line contains the point (13,-2) and (3,-2)
The slope of line is given as:
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
Where, "m" is the slope of line
Here given points are (13,-2) and (3,-2)
[tex](x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)[/tex]
Substituting the values in formula, we get,
[tex]m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0[/tex]
Thus the slope of line is 0
