Answer:
for x = 14, the given ABCD is a RECTANGLE.
Step-by-step explanation:
Given : ABCD is a quadrilateral.
E is the intersection points of the diagonal AC and BD.
AE = x+10, and BE= 3x -18
Now, as we know:
IN A RECTANGLES , DIAGONALS BISECT EACH OTHER.
⇒ E is the mid point of AC and BD respectively.
⇒ AE = BE
⇒ x+10 = 3 x - 18
or, 10 + 18 = 3 x - x
or, 2 x = 28
or, x = 28/2 = 14 ⇒ x = 14
Hence, for x = 14, the given ABCD is a RECTANGLE.
