Answer:
[tex]x\ values\ of\ x-intercepts\ are\ x=-2\ and\ x=-3[/tex]
Step-by-step explanation:
x-intercepts: The point at which curve passes through the [tex]x-axis[/tex] that is when [tex]y=0[/tex].
The given curve is [tex]y=x^2+5x+6[/tex].
To get x-intercepts substitute [tex]y=0[/tex].
[tex]x^2+5x+6=0\\\\x^2+3x+2x+6=0\\\\x(x+3)+2(x+3)=0\\\\(x+3)(x+2)=0\\\\Hence\ x=-3,\ x=-2[/tex]
