Answer:
Explanation:
Given
Heat capacity of Calorimeter [tex]C=3.18\ KJ/K[/tex]
no of moles [tex]n=0.0038\ mol[/tex]
initial temperature [tex]T_i=25^{\circ}C[/tex]
Final Temperature [tex]T_f=27.3^{\circ}C[/tex]
increase in temperature [tex]\Delta T=27.3-25=2.3^{\circ}C[/tex]
Energy released by combustion of 0.0038 mole is given by
[tex]Q=3.18\times \Delta T[/tex]
[tex]Q=3.18\times 2.3=7.314\ kJ[/tex]
This Energy is associated with 0.0038 moles therefore energy associated with 1 mole is [tex]=\frac{7.314}{0.0038}=1.924\times 10^{3}\ kJ[/tex]
