Answer:
0.81452 atm
Explanation:
[tex]P_1[/tex] = Initial pressure = 1.43 L
[tex]V_1=V_2[/tex] = Volume
[tex]T_1[/tex] = Initial temperature = (28+273.15) K
[tex]T_2[/tex] = Final temperature = (-35+273.15) K
[tex]P_2[/tex] = Final pressure
From the ideal gas law we have
[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1V_1T_2}{T_2V_2}\\\Rightarrow P_2=\dfrac{1.03\times 1.43\times (273.15-35)}{(273.15+28)1.43}\\\Rightarrow P_2=0.81452\ atm[/tex]
The pressure in the cylinder is 0.81452 atm
