Answer:
LT⁻¹
Explanation:
Assuming the given expression is
x = A t³ + B t.........(1)
x is the distance
we have to calculate dimension of dx/dt
from expression (1)
x = A t³
[tex]A = \dfrac{L}{T^3}[/tex]
A = LT⁻³
x = B t
B = LT⁻¹
now,
dx/dt = 3At^2 + B
from rule of dimension
dimension of dx/dt is equal to dimension of At^2
dx/dt = A t²
dx/dt = LT⁻³ x T²
dx/dt = LT⁻¹
hence, dimension of dx/dt is equal to LT⁻¹
