Answer:
[tex]x_{123} x^{2} \sqrt{x} \neq \sqrt{x} \sqrt{x} \geq \neq \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] x^{2} \pi[/tex]
Step-by-step explanation:
because im smart
see explanation
The measure of arc AE is
AE = 360° - (100 + 40 + 60)° = 360° - 200° = 160°
∠ BCD = 0.5( m arc AE - m arc BD ), that is
x = 0.5(160 - 40) = 0.5 × 120 = 60
