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  • 20-12-2019
  • Mathematics
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(x²+y²+2xy+1)dy=(x+y)dx​

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Lidpras
Lidpras Lidpras
  • 20-12-2019

[tex]( {x}^{2} + {y}^{2} + 2xy + 1)dy = (x + y)dx \\ \frac{dy}{dx} = \frac{x + y}{ {x}^{2} + {y}^{2} + 2xy + 1 } [/tex]

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