Answer:
x intercepts at (-3,0), and (1,0)
there is a minimum at (-1,-4)
Step-by-step explanation:
Please see attached image for the requested graph of the function [tex]f(x) = x^2+2x-3[/tex], and observe that the crossings of the x-axis are at the points (-3,0), and (1,0) , marked in red in the image.
We can also see that there is no maximum, but a minimum value, and located at the point (-1,-4) [marked in green in the image]
