For this case we have the following system of equations:
[tex]6x-y = 4\\y = 4x + 2[/tex]
Substituting the second equation into the first we have:
[tex]6x- (4x + 2) = 4\\6x-4x-2 = 4\\2x = 4 + 2\\2x = 6\\x = \frac {6} {2}\\x = 3[/tex]
We find the value of the variable "y":
[tex]y = 4x + 2\\y = 4 (3) +2\\y = 12 + 2\\y = 14[/tex]
Finally, the system solution is:
[tex](x, y) :( 3,14)[/tex]
Answer:
The value of "x" in the system solution is 3.
