hollyalicej hollyalicej
  • 18-10-2019
  • Mathematics
contestada

Find f'(x) if f(x) = (2/(x^1/3)) + 3 cos x + x^pi

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LammettHash
LammettHash LammettHash
  • 18-10-2019

The derivative of [tex]f[/tex] is

[tex]f'(x)=\left(2x^{-1/3}+3\cos x+x^\pi\right)'[/tex]

[tex]f'(x)=\left(2x^{-1/3}\right)'+(3\cos x)'+\left(x^\pi\right)'[/tex]

By the power rule,

[tex]f'(x)=-\dfrac23x^{-4/3}+(3\cos x)'+\pi x^{\pi-1}[/tex]

The derivative of [tex]\cos x[/tex] is [tex]-\sin x[/tex]:

[tex]f'(x)=-\dfrac23x^{-4/3}-3\sin x+\pi x^{\pi-1}[/tex]

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