MooSnuckel301 MooSnuckel301
  • 16-10-2019
  • Chemistry
contestada

Question (1 point) 1st attempt The spectrum of a blackbody has a peak wavelength of 6.90x10 7 meters. What is its temperature,in kelvins?

Respuesta :

Mergus Mergus
  • 17-10-2019

Answer:

4202.8985 K

Explanation:

Using Wien's displacement law which states that the temperature and the wavelength of the blackbody radiation are inversely proportional.

So,

λmax= b/T

Where,

λmax is the peak of wavelength [tex]6.90\times 10^{-7}\ m[/tex]

b is the Wien's displacement constant having value as [tex]2.9\times 10^{-3}\  m K[/tex]

T is the Absolute Temperature in Kelvin.s

So,

T = b/λmax = [tex]\frac{2.9\times 10^{-3}}{6.90\times 10^{-7}}[/tex] = 4202.8985 K

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