Respuesta :

meerkat18
Given:
Radius = 3 cm
length of minor arc = 5/2π

length of the minor arc = 2 π r (x/360°)
5/2π = 2 π r (x/360°)
5/2 * 3.14 = 2 * 3.14 * 3 (x/360°)
5/6.28 = 18.84 (x/360°)
6.28(5/6.28) = 6.28(18.84)(x/360°)
5 * 360° = 118.32x
1800 / 118.32 = x
15.21 = x