Answer:
The partial pressure of H2 = 0.8 barr
Explanation:
Step1: Let's consider the mass of this mixture is 100g.
⇒ 20% of the mixture = hydrogen = 20g
⇒ 80% of the mixture = oxygen = 80g
Step 2 : Calculating mole
mole = Mass / molar mass
⇒mole hydrogen = 20g / 2 = 10 moles
⇒ mole oxygen = 80g / 32 = 2.5 moles
Step 3: Calculating the partial pressure.
pH2 = XH2 x ptotal = (nH2 / nH2 + nO2) x ptotal =10 / (10 +2.5) x 1 = 0.8 barr
The partial pressure of H2 = 0.8 barr
