Respuesta :

sqdancefan

Answer:

  6x^2·y^6·√(2x)

Step-by-step explanation:

[tex]\sqrt{72x^5y^{12}}=\sqrt{2x(6x^2y^6)^2}=6x^2y^6\sqrt{2x}[/tex]

As in the answer above, parentheses are useful for identifying what is under the radical and what is not.