Answer:
45.93°
Explanation:
The angle of incidence is given as 32.7°
The refractive index of the water that is [tex]n_1=1.33[/tex]
Refractive index of the air that is [tex]n_2=1[/tex] (because the refractive index of air is 1 )
We have to find the angle at which the light leave the water means angle of refraction
So according to snell's law [tex]n_1sini=n_2sinr[/tex]
[tex]1.33sin32.7=1\times sinr[/tex]
[tex]sinr=0.7185[/tex]
r =45.93°
So the light leave the water at an angle of 45.93°
