Answer:
[tex]\rho=1.98 \frac{g}{cm^3}[/tex]
Explanation:
Molecular mass of Cesium M=132.9 g/mol
To find density
[tex]\rho=\dfrac{Z\times M}{a^3N_a}[/tex]
Where [tex]N_a=6.022\times 10^{23}[/tex]
a is the lattice parameter,Z=2 for body centered.
[tex]\rho=\dfrac{2\times 132.9}{(6.06\times 10^{-8})^3\times 6.022\times 10^{23}}[/tex]
So [tex]\rho=1.98 \frac{g}{cm^3}[/tex]
