Answer:
6.3 m/s²
Explanation:
m = mass of the skydiver = 80.0 kg
k = constant
v = speed at any time
a = acceleration
W = weight = mg = 80 x 9.8 = 784 N
Force equation for the motion of skydiver is given as
W - k v² = ma
at v = 50 m/s , a = 0
784 - k (50)² = (80) (0)
k = 0.3136
At v = 30 m/s, equation can be written as
W - k v² = ma
784 - (0.3136) (30)² = 80 a
a = 6.3 m/s²
