Answer: [tex]AC=10.5[/tex]
Step-by-step explanation:
Assuming that [tex]b=AC[/tex] and given the following equation:
[tex]tan(55\°)=\frac{15}{b}[/tex]
You need to solve for "b" in order to find the lenght of AC asked in the exercise.
Therefore, with this procedure you get that the lenght of AC is the following:
[tex]\frac{15}{tan(55\°)}=b[/tex]
[tex]b=AC=10.5[/tex]
