Answer:
[tex]4x^5\sqrt[3]{3x}[/tex]
Step-by-step explanation:
The product will be written as:
[tex]\sqrt[3]{16x^7}*\sqrt[3]{12x^9}[/tex]
As both the radicals have same root 3 so,
[tex]= \sqrt[3]{16x^7 * 12x^9}[/tex]
The powers of x will be added as the base is same
[tex]=\sqrt[3]{16*12 * x^{(7+9)}}\\=\sqrt[3]{192x^{16}}\\[/tex]
We have to break the terms so that the powers can be written as a multiple of 3
[tex]=\sqrt[3]{64*3*x^{15}*x}\\ =\sqrt[3]{(4^3)*3*(x^{3*5})*x}\\ Applying\ cube\ root\\= 4x^5\sqrt[3]{3x}[/tex]
