Answer:
[tex]\boxed{ \text{0.75 mol}}[/tex]
Explanation:
(a) Balanced equation
2NaBH₄ + H₂SO₄ ⟶ 2H₂ + Na₂SO₄ + B₂H₆
(b) Calculation
You want to convert moles of NaBH₄ to moles of B₂H₆
The molar ratio is 1 mol B₂H₆:2 mol NaBH₄
[tex]\text{Moles of B$_{2}$H$_{6}$} =\text{1.5 mol NaBH$_{4}$} \times \dfrac{\text{1 mol B$_{2}$H$_{6}$}}{\text{2 mol NaBH$_{4}$}} = \textbf{0.75 mol B$_{2}$H$_{6}$}\\\\\text{The reaction will produce }\boxed{ \textbf{0.75 mol of B$_{2}$H$_{6}$}}[/tex]
