Answer:
H
Step-by-step explanation:
The parallel line BC divides the sides AD and AE in proportion, that is
[tex]\frac{AB}{BD}[/tex] = [tex]\frac{AC}{CE}[/tex], that is
[tex]\frac{2}{3}[/tex] = [tex]\frac{AC}{4}[/tex] ( cross- multiply )
3AC = 8 ( divide both sides by 3 )
AC = [tex]\frac{8}{3}[/tex] = 2 [tex]\frac{2}{3}[/tex], hence
AE = AC + CE
= 2 [tex]\frac{2}{3}[/tex] + 4 = 6 [tex]\frac{2}{3}[/tex] → H
