For this case we must solve the following equation for x:
[tex]\frac {1} {3} (6x-15) = \frac {1} {2} (10x-4)[/tex]
We apply distributive property to the terms of parentheses:
[tex]2x-5 = 5x-2[/tex]
We subtract 5x on both sides of the equation:
[tex]2x-5x-5 = -2\\-3x-5 = -2[/tex]
Suamos 5 on both sides of the equation:
[tex]-3x = -2 + 5\\-3x = 3\\x = - \frac {3} {3}\\x = -1[/tex]
Answer:
[tex]x = -1[/tex]
