Seudónimo Seudónimo
  • 18-04-2019
  • Mathematics
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Help please!!! And thanks to whoever does

Help please And thanks to whoever does class=

Respuesta :

m1k
m1k m1k
  • 18-04-2019

I’m sorry I can’t do that on the top of my head but try using a graph calculator or Photomath to help. I hope this helped.

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SoLaraS2
SoLaraS2 SoLaraS2
  • 18-04-2019

Answer:

B) x<_5

Why:

3x-8<_23

3x<_31

x<_31/3

-4x+26>_6

-4x>_-20

Multiplying by -1 in these cases, inverts the inequality

4x<_20

x<_5

So x has to be less or equal to 5, as 31/3 is still a higher number than 5, so all solutions for the second equation would apply to x.

Hope you get it!

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